Base | Representation |
---|---|
bin | 11110111111110101001… |
… | …000000001000101100111 |
3 | 21112122012211002100111101 |
4 | 132333311020001011213 |
5 | 234344442030043142 |
6 | 4310321512420531 |
7 | 306616251366163 |
oct | 36776510010547 |
9 | 7478184070441 |
10 | 2130121331047 |
11 | 751419a60806 |
12 | 2a49b93a7747 |
13 | 125b3c60a908 |
14 | 751540ddca3 |
15 | 3a62180b0b7 |
hex | 1eff5201167 |
2130121331047 has 2 divisors, whose sum is σ = 2130121331048. Its totient is φ = 2130121331046.
The previous prime is 2130121331033. The next prime is 2130121331071. The reversal of 2130121331047 is 7401331210312.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2130121331047 is a prime.
It is a super-2 number, since 2×21301213310472 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2130121331027) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1065060665523 + 1065060665524.
It is an arithmetic number, because the mean of its divisors is an integer number (1065060665524).
Almost surely, 22130121331047 is an apocalyptic number.
2130121331047 is a deficient number, since it is larger than the sum of its proper divisors (1).
2130121331047 is an equidigital number, since it uses as much as digits as its factorization.
2130121331047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3024, while the sum is 28.
Adding to 2130121331047 its reverse (7401331210312), we get a palindrome (9531452541359).
The spelling of 2130121331047 in words is "two trillion, one hundred thirty billion, one hundred twenty-one million, three hundred thirty-one thousand, forty-seven".
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