Base | Representation |
---|---|
bin | 1001101011111100110010… |
… | …00110000001010110101111 |
3 | 2210102101102000021120121011 |
4 | 10311332121012001112233 |
5 | 10243000041144011302 |
6 | 113145404243450051 |
7 | 4325653231463233 |
oct | 465763106012657 |
9 | 83371360246534 |
10 | 21301311313327 |
11 | 6872920a04351 |
12 | 2480406086927 |
13 | bb6921c77706 |
14 | 538dbba305c3 |
15 | 26e168e835d7 |
hex | 135f991815af |
21301311313327 has 2 divisors, whose sum is σ = 21301311313328. Its totient is φ = 21301311313326.
The previous prime is 21301311313277. The next prime is 21301311313357. The reversal of 21301311313327 is 72331311310312.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21301311313327 - 215 = 21301311280559 is a prime.
It is a super-3 number, since 3×213013113133273 (a number of 41 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21301311313357) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10650655656663 + 10650655656664.
It is an arithmetic number, because the mean of its divisors is an integer number (10650655656664).
Almost surely, 221301311313327 is an apocalyptic number.
21301311313327 is a deficient number, since it is larger than the sum of its proper divisors (1).
21301311313327 is an equidigital number, since it uses as much as digits as its factorization.
21301311313327 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6804, while the sum is 31.
Adding to 21301311313327 its reverse (72331311310312), we get a palindrome (93632622623639).
The spelling of 21301311313327 in words is "twenty-one trillion, three hundred one billion, three hundred eleven million, three hundred thirteen thousand, three hundred twenty-seven".
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