Base | Representation |
---|---|
bin | 11110111111110111110… |
… | …110101110111100101111 |
3 | 21112122100000021021112011 |
4 | 132333313312232330233 |
5 | 234400040241210301 |
6 | 4310330230222051 |
7 | 306620345604415 |
oct | 36776766567457 |
9 | 7478300237464 |
10 | 2130167131951 |
11 | 7514428a36a1 |
12 | 2a4a107b4927 |
13 | 125b48c55941 |
14 | 7515a2232b5 |
15 | 3a625856a51 |
hex | 1eff7daef2f |
2130167131951 has 2 divisors, whose sum is σ = 2130167131952. Its totient is φ = 2130167131950.
The previous prime is 2130167131921. The next prime is 2130167132011. The reversal of 2130167131951 is 1591317610312.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2130167131951 - 27 = 2130167131823 is a prime.
It is a super-2 number, since 2×21301671319512 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2130167131921) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1065083565975 + 1065083565976.
It is an arithmetic number, because the mean of its divisors is an integer number (1065083565976).
Almost surely, 22130167131951 is an apocalyptic number.
2130167131951 is a deficient number, since it is larger than the sum of its proper divisors (1).
2130167131951 is an equidigital number, since it uses as much as digits as its factorization.
2130167131951 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 34020, while the sum is 40.
The spelling of 2130167131951 in words is "two trillion, one hundred thirty billion, one hundred sixty-seven million, one hundred thirty-one thousand, nine hundred fifty-one".
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