2130210211320 has 192 divisors, whose sum is σ = 6955021513440. Its totient is φ = 565445836800.

The previous prime is 2130210211319. The next prime is 2130210211369. The reversal of 2130210211320 is 231120120312.

2130210211320 is a `hidden beast` number, since 2 + 130 + 2 + 1 + 0 + 211 + 320 = 666.

It is a super-2 number, since 2×2130210211320² (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 2130210211293 and 2130210211302.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 270774027 + ... + 270781893.

Almost surely, 2^{2130210211320} is an apocalyptic number.

2130210211320 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 2130210211320, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (3477510756720).

2130210211320 is an abundant number, since it is smaller than the sum of its proper divisors (4824811302120).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2130210211320 is a wasteful number, since it uses less digits than its factorization.

2130210211320 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11246 (or 11239 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 2130210211320 its reverse (231120120312), we get a palindrome (2361330331632).

The spelling of 2130210211320 in words is "two trillion, one hundred thirty billion, two hundred ten million, two hundred eleven thousand, three hundred twenty".