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213024414017 is a prime number
BaseRepresentation
bin1100011001100100111…
…1101001100101000001
3202100212001000110200202
43012121033221211001
511442233222222032
6241510112254545
721250641433352
oct3063117514501
9670761013622
10213024414017
1182385801228
1235351541455
131711b78b42c
14a44bba3d29
15581bae9d62
hex31993e9941

213024414017 has 2 divisors, whose sum is σ = 213024414018. Its totient is φ = 213024414016.

The previous prime is 213024413993. The next prime is 213024414019. The reversal of 213024414017 is 710414420312.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 164271332416 + 48753081601 = 405304^2 + 220801^2 .

It is a cyclic number.

It is not a de Polignac number, because 213024414017 - 220 = 213023365441 is a prime.

Together with 213024414019, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (213024414019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106512207008 + 106512207009.

It is an arithmetic number, because the mean of its divisors is an integer number (106512207009).

Almost surely, 2213024414017 is an apocalyptic number.

It is an amenable number.

213024414017 is a deficient number, since it is larger than the sum of its proper divisors (1).

213024414017 is an equidigital number, since it uses as much as digits as its factorization.

213024414017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5376, while the sum is 29.

Adding to 213024414017 its reverse (710414420312), we get a palindrome (923438834329).

The spelling of 213024414017 in words is "two hundred thirteen billion, twenty-four million, four hundred fourteen thousand, seventeen".