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2130311301 = 3710103767
BaseRepresentation
bin111111011111001…
…1111100010000101
312111110120000201120
41332332133202011
513330324430201
6551215544153
7103535230056
oct17676374205
95443500646
102130311301
119a3561458
124b552b059
1327c471741
14162cda72d
15c7053536
hex7ef9f885

2130311301 has 4 divisors (see below), whose sum is σ = 2840415072. Its totient is φ = 1420207532.

The previous prime is 2130311273. The next prime is 2130311317. The reversal of 2130311301 is 1031130312.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2130311301 - 25 = 2130311269 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2130311341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 355051881 + ... + 355051886.

It is an arithmetic number, because the mean of its divisors is an integer number (710103768).

Almost surely, 22130311301 is an apocalyptic number.

It is an amenable number.

2130311301 is a deficient number, since it is larger than the sum of its proper divisors (710103771).

2130311301 is an equidigital number, since it uses as much as digits as its factorization.

2130311301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 710103770.

The product of its (nonzero) digits is 54, while the sum is 15.

The square root of 2130311301 is about 46155.2954816671. The cubic root of 2130311301 is about 1286.7110296912.

Adding to 2130311301 its reverse (1031130312), we get a palindrome (3161441613).

The spelling of 2130311301 in words is "two billion, one hundred thirty million, three hundred eleven thousand, three hundred one".

Divisors: 1 3 710103767 2130311301