Base | Representation |
---|---|
bin | 11111000000000000100… |
… | …011100100000101100111 |
3 | 21112122201011221022100002 |
4 | 133000000203210011213 |
5 | 234400340123223141 |
6 | 4310352523011515 |
7 | 306624100410206 |
oct | 37000043440547 |
9 | 7478634838302 |
10 | 2130313101671 |
11 | 751508232927 |
12 | 2a4a51669b9b |
13 | 125b70273261 |
14 | 7517177d23d |
15 | 3a63358be9b |
hex | 1f0008e4167 |
2130313101671 has 2 divisors, whose sum is σ = 2130313101672. Its totient is φ = 2130313101670.
The previous prime is 2130313101599. The next prime is 2130313101677. The reversal of 2130313101671 is 1761013130312.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2130313101671 - 230 = 2129239359847 is a prime.
It is a super-2 number, since 2×21303131016712 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2130313101677) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1065156550835 + 1065156550836.
It is an arithmetic number, because the mean of its divisors is an integer number (1065156550836).
Almost surely, 22130313101671 is an apocalyptic number.
2130313101671 is a deficient number, since it is larger than the sum of its proper divisors (1).
2130313101671 is an equidigital number, since it uses as much as digits as its factorization.
2130313101671 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2268, while the sum is 29.
Adding to 2130313101671 its reverse (1761013130312), we get a palindrome (3891326231983).
The spelling of 2130313101671 in words is "two trillion, one hundred thirty billion, three hundred thirteen million, one hundred one thousand, six hundred seventy-one".
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