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2130320131981 is a prime number
BaseRepresentation
bin11111000000000000111…
…110011000011110001101
321112122201200011111002221
4133000000332120132031
5234400343423210411
64310353333415341
7306624214230556
oct37000076303615
97478650144087
102130320131981
117515111a48a8
122a4a53a9a551
13125b718651c2
147517268d32d
153a633eca071
hex1f000f9878d

2130320131981 has 2 divisors, whose sum is σ = 2130320131982. Its totient is φ = 2130320131980.

The previous prime is 2130320131957. The next prime is 2130320132053. The reversal of 2130320131981 is 1891310230312.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2126539726756 + 3780405225 = 1458266^2 + 61485^2 .

It is a cyclic number.

It is not a de Polignac number, because 2130320131981 - 25 = 2130320131949 is a prime.

It is a super-2 number, since 2×21303201319812 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2130320132981) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1065160065990 + 1065160065991.

It is an arithmetic number, because the mean of its divisors is an integer number (1065160065991).

Almost surely, 22130320131981 is an apocalyptic number.

It is an amenable number.

2130320131981 is a deficient number, since it is larger than the sum of its proper divisors (1).

2130320131981 is an equidigital number, since it uses as much as digits as its factorization.

2130320131981 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7776, while the sum is 34.

The spelling of 2130320131981 in words is "two trillion, one hundred thirty billion, three hundred twenty million, one hundred thirty-one thousand, nine hundred eighty-one".