Base | Representation |
---|---|
bin | 110000011100001011000001… |
… | …010011110001000000011111 |
3 | 1000221022122011222120120122021 |
4 | 300130023001103301000133 |
5 | 210410440422004002401 |
6 | 2033034123550201011 |
7 | 62605535406553165 |
oct | 6034130123610037 |
9 | 1027278158516567 |
10 | 213042211000351 |
11 | 619777701243a7 |
12 | 1ba890114b3167 |
13 | 91b4a430b0185 |
14 | 3a87425b19235 |
15 | 1996ab439e2a1 |
hex | c1c2c14f101f |
213042211000351 has 2 divisors, whose sum is σ = 213042211000352. Its totient is φ = 213042211000350.
The previous prime is 213042211000337. The next prime is 213042211000433. The reversal of 213042211000351 is 153000112240312.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 213042211000351 - 219 = 213042210476063 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (213042212000351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106521105500175 + 106521105500176.
It is an arithmetic number, because the mean of its divisors is an integer number (106521105500176).
Almost surely, 2213042211000351 is an apocalyptic number.
213042211000351 is a deficient number, since it is larger than the sum of its proper divisors (1).
213042211000351 is an equidigital number, since it uses as much as digits as its factorization.
213042211000351 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 213042211000351 its reverse (153000112240312), we get a palindrome (366042323240663).
The spelling of 213042211000351 in words is "two hundred thirteen trillion, forty-two billion, two hundred eleven million, three hundred fifty-one", and thus it is an aban number.
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