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21310010313 = 349114467081
BaseRepresentation
bin10011110110001011…
…001111001111001001
32001000010112200120020
4103312023033033021
5322120330312223
613442323251053
71353040045644
oct236613171711
961003480506
1021310010313
119045a44179
124168819a89
132017c09077
141062290a5b
1584ac871e3
hex4f62cf3c9

21310010313 has 8 divisors (see below), whose sum is σ = 28471217376. Its totient is φ = 14177738400.

The previous prime is 21310010299. The next prime is 21310010317. The reversal of 21310010313 is 31301001312.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 21310010313 - 228 = 21041574857 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 21310010292 and 21310010301.

It is not an unprimeable number, because it can be changed into a prime (21310010317) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7232068 + ... + 7235013.

It is an arithmetic number, because the mean of its divisors is an integer number (3558902172).

Almost surely, 221310010313 is an apocalyptic number.

It is an amenable number.

21310010313 is a deficient number, since it is larger than the sum of its proper divisors (7161207063).

21310010313 is a wasteful number, since it uses less digits than its factorization.

21310010313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14467575.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 21310010313 its reverse (31301001312), we get a palindrome (52611011625).

Subtracting 21310010313 from its reverse (31301001312), we obtain a palindrome (9990990999).

The spelling of 21310010313 in words is "twenty-one billion, three hundred ten million, ten thousand, three hundred thirteen".

Divisors: 1 3 491 1473 14467081 43401243 7103336771 21310010313