Base | Representation |
---|---|
bin | 10011110110001011… |
… | …100101101111010001 |
3 | 2001000010201100222212 |
4 | 103312023211233101 |
5 | 322120341234411 |
6 | 13442325241505 |
7 | 1353040611443 |
oct | 236613455721 |
9 | 61003640885 |
10 | 21310102481 |
11 | 9045aa7448 |
12 | 4168863295 |
13 | 2017c3bcc5 |
14 | 10622b6493 |
15 | 84aca468b |
hex | 4f62e5bd1 |
21310102481 has 2 divisors, whose sum is σ = 21310102482. Its totient is φ = 21310102480.
The previous prime is 21310102421. The next prime is 21310102487. The reversal of 21310102481 is 18420101312.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 21308700625 + 1401856 = 145975^2 + 1184^2 .
It is a cyclic number.
It is not a de Polignac number, because 21310102481 - 214 = 21310086097 is a prime.
It is a super-2 number, since 2×213101024812 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (21310102487) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10655051240 + 10655051241.
It is an arithmetic number, because the mean of its divisors is an integer number (10655051241).
Almost surely, 221310102481 is an apocalyptic number.
It is an amenable number.
21310102481 is a deficient number, since it is larger than the sum of its proper divisors (1).
21310102481 is an equidigital number, since it uses as much as digits as its factorization.
21310102481 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 23.
Adding to 21310102481 its reverse (18420101312), we get a palindrome (39730203793).
The spelling of 21310102481 in words is "twenty-one billion, three hundred ten million, one hundred two thousand, four hundred eighty-one".
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