Base | Representation |
---|---|
bin | 11111000000101010110… |
… | …000110010101011100111 |
3 | 21112201112112101001122001 |
4 | 133000222300302223213 |
5 | 234403312412244031 |
6 | 4310551100150131 |
7 | 306650456302021 |
oct | 37005260625347 |
9 | 7481475331561 |
10 | 2131021212391 |
11 | 751840a119a5 |
12 | 2a500a838347 |
13 | 125c53b92296 |
14 | 751db829011 |
15 | 3a675812861 |
hex | 1f02ac32ae7 |
2131021212391 has 2 divisors, whose sum is σ = 2131021212392. Its totient is φ = 2131021212390.
The previous prime is 2131021212377. The next prime is 2131021212469. The reversal of 2131021212391 is 1932121201312.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2131021212391 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2131021212791) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1065510606195 + 1065510606196.
It is an arithmetic number, because the mean of its divisors is an integer number (1065510606196).
Almost surely, 22131021212391 is an apocalyptic number.
2131021212391 is a deficient number, since it is larger than the sum of its proper divisors (1).
2131021212391 is an equidigital number, since it uses as much as digits as its factorization.
2131021212391 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 28.
The spelling of 2131021212391 in words is "two trillion, one hundred thirty-one billion, twenty-one million, two hundred twelve thousand, three hundred ninety-one".
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