Base | Representation |
---|---|
bin | 11111000000101010111… |
… | …000110010110100101111 |
3 | 21112201112200022122011222 |
4 | 133000222320302310233 |
5 | 234403313431411002 |
6 | 4310551213133555 |
7 | 306650513156615 |
oct | 37005270626457 |
9 | 7481480278158 |
10 | 2131023310127 |
11 | 751842114a68 |
12 | 2a500b48a2bb |
13 | 125c5444804a |
14 | 751dbc136b5 |
15 | 3a675ac91a2 |
hex | 1f02ae32d2f |
2131023310127 has 2 divisors, whose sum is σ = 2131023310128. Its totient is φ = 2131023310126.
The previous prime is 2131023310109. The next prime is 2131023310211. The reversal of 2131023310127 is 7210133201312.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2131023310127 - 220 = 2131022261551 is a prime.
It is a super-2 number, since 2×21310233101272 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2131023310096 and 2131023310105.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2131023310327) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1065511655063 + 1065511655064.
It is an arithmetic number, because the mean of its divisors is an integer number (1065511655064).
Almost surely, 22131023310127 is an apocalyptic number.
2131023310127 is a deficient number, since it is larger than the sum of its proper divisors (1).
2131023310127 is an equidigital number, since it uses as much as digits as its factorization.
2131023310127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 26.
Adding to 2131023310127 its reverse (7210133201312), we get a palindrome (9341156511439).
The spelling of 2131023310127 in words is "two trillion, one hundred thirty-one billion, twenty-three million, three hundred ten thousand, one hundred twenty-seven".
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