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21310301013 = 37103433671
BaseRepresentation
bin10011110110001100…
…010110001101010101
32001000011002110022220
4103312030112031111
5322120414113023
613442333412553
71353042366321
oct236614261525
961004073286
1021310301013
119046122621
12416893a159
132017cab491
141062328981
1584ace33e3
hex4f6316355

21310301013 has 4 divisors (see below), whose sum is σ = 28413734688. Its totient is φ = 14206867340.

The previous prime is 21310300951. The next prime is 21310301059. The reversal of 21310301013 is 31010301312.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 21310301013 - 217 = 21310169941 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 21310300983 and 21310301001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21310301083) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3551716833 + ... + 3551716838.

It is an arithmetic number, because the mean of its divisors is an integer number (7103433672).

Almost surely, 221310301013 is an apocalyptic number.

It is an amenable number.

21310301013 is a deficient number, since it is larger than the sum of its proper divisors (7103433675).

21310301013 is an equidigital number, since it uses as much as digits as its factorization.

21310301013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7103433674.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 21310301013 its reverse (31010301312), we get a palindrome (52320602325).

The spelling of 21310301013 in words is "twenty-one billion, three hundred ten million, three hundred one thousand, thirteen".

Divisors: 1 3 7103433671 21310301013