Base | Representation |
---|---|
bin | 1100011001110111101… |
… | …1111000111100010011 |
3 | 202101001112010011012121 |
4 | 3012131323320330103 |
5 | 11442413344321042 |
6 | 241522003235111 |
7 | 21252615430321 |
oct | 3063573707423 |
9 | 671045104177 |
10 | 213103120147 |
11 | 82416179315 |
12 | 35373978a97 |
13 | 17131b878c8 |
14 | a458410d11 |
15 | 5823995367 |
hex | 319def8f13 |
213103120147 has 2 divisors, whose sum is σ = 213103120148. Its totient is φ = 213103120146.
The previous prime is 213103120123. The next prime is 213103120189. The reversal of 213103120147 is 741021301312.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 213103120147 - 211 = 213103118099 is a prime.
It is not a weakly prime, because it can be changed into another prime (213103126147) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106551560073 + 106551560074.
It is an arithmetic number, because the mean of its divisors is an integer number (106551560074).
Almost surely, 2213103120147 is an apocalyptic number.
213103120147 is a deficient number, since it is larger than the sum of its proper divisors (1).
213103120147 is an equidigital number, since it uses as much as digits as its factorization.
213103120147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1008, while the sum is 25.
Adding to 213103120147 its reverse (741021301312), we get a palindrome (954124421459).
The spelling of 213103120147 in words is "two hundred thirteen billion, one hundred three million, one hundred twenty thousand, one hundred forty-seven".
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