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21310355433 = 37103451811
BaseRepresentation
bin10011110110001100…
…100011011111101001
32001000011012012222110
4103312030203133221
5322120422333213
613442334512533
71353043014063
oct236614433751
961004165873
1021310355433
11904615a4a4
124168965749
132017cca193
141062340733
1584ad045c3
hex4f63237e9

21310355433 has 4 divisors (see below), whose sum is σ = 28413807248. Its totient is φ = 14206903620.

The previous prime is 21310355419. The next prime is 21310355441. The reversal of 21310355433 is 33455301312.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 21310355433 - 25 = 21310355401 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 21310355433.

It is not an unprimeable number, because it can be changed into a prime (21312355433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3551725903 + ... + 3551725908.

It is an arithmetic number, because the mean of its divisors is an integer number (7103451812).

Almost surely, 221310355433 is an apocalyptic number.

It is an amenable number.

21310355433 is a deficient number, since it is larger than the sum of its proper divisors (7103451815).

21310355433 is an equidigital number, since it uses as much as digits as its factorization.

21310355433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7103451814.

The product of its (nonzero) digits is 16200, while the sum is 30.

Adding to 21310355433 its reverse (33455301312), we get a palindrome (54765656745).

The spelling of 21310355433 in words is "twenty-one billion, three hundred ten million, three hundred fifty-five thousand, four hundred thirty-three".

Divisors: 1 3 7103451811 21310355433