Base | Representation |
---|---|
bin | 11111000000101111011… |
… | …101010110000000110001 |
3 | 21112201202000121220022221 |
4 | 133000233131112000301 |
5 | 234403443100002210 |
6 | 4311002553001041 |
7 | 306652434056263 |
oct | 37005735260061 |
9 | 7481660556287 |
10 | 2131100000305 |
11 | 751881435481 |
12 | 2a50310b3181 |
13 | 125c672b9a53 |
14 | 75208097b33 |
15 | 3a67c6c71da |
hex | 1f02f756031 |
2131100000305 has 4 divisors (see below), whose sum is σ = 2557320000372. Its totient is φ = 1704880000240.
The previous prime is 2131100000261. The next prime is 2131100000329. The reversal of 2131100000305 is 5030000011312.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 518006954529 + 1613093045776 = 719727^2 + 1270076^2 .
It is not a de Polignac number, because 2131100000305 - 219 = 2131099476017 is a prime.
It is a super-2 number, since 2×21311000003052 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 213110000026 + ... + 213110000035.
It is an arithmetic number, because the mean of its divisors is an integer number (639330000093).
Almost surely, 22131100000305 is an apocalyptic number.
It is an amenable number.
2131100000305 is a deficient number, since it is larger than the sum of its proper divisors (426220000067).
2131100000305 is an equidigital number, since it uses as much as digits as its factorization.
2131100000305 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 426220000066.
The product of its (nonzero) digits is 90, while the sum is 16.
Adding to 2131100000305 its reverse (5030000011312), we get a palindrome (7161100011617).
The spelling of 2131100000305 in words is "two trillion, one hundred thirty-one billion, one hundred million, three hundred five", and thus it is an aban number.
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