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2131101310231 is a prime number
BaseRepresentation
bin11111000000101111100…
…010010101110100010111
321112201202010002110012201
4133000233202111310113
5234403443413411411
64311003041025331
7306652451153305
oct37005742256427
97481663073181
102131101310231
1175188214a663
122a5031625247
13125c6765805a
1475208319275
153a67c8853c1
hex1f02f895d17

2131101310231 has 2 divisors, whose sum is σ = 2131101310232. Its totient is φ = 2131101310230.

The previous prime is 2131101310213. The next prime is 2131101310237. The reversal of 2131101310231 is 1320131011312.

Together with previous prime (2131101310213) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2131101310231 - 29 = 2131101309719 is a prime.

It is a super-2 number, since 2×21311013102312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2131101310199 and 2131101310208.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2131101310237) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1065550655115 + 1065550655116.

It is an arithmetic number, because the mean of its divisors is an integer number (1065550655116).

Almost surely, 22131101310231 is an apocalyptic number.

2131101310231 is a deficient number, since it is larger than the sum of its proper divisors (1).

2131101310231 is an equidigital number, since it uses as much as digits as its factorization.

2131101310231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 2131101310231 its reverse (1320131011312), we get a palindrome (3451232321543).

The spelling of 2131101310231 in words is "two trillion, one hundred thirty-one billion, one hundred one million, three hundred ten thousand, two hundred thirty-one".