Base | Representation |
---|---|
bin | 1100011001111001011… |
… | …1010100100110100011 |
3 | 202101002000122111122202 |
4 | 3012132113110212203 |
5 | 11442422214430311 |
6 | 241522421323415 |
7 | 21253033521011 |
oct | 3063627244643 |
9 | 671060574582 |
10 | 213110311331 |
11 | 8241a240145 |
12 | 3537626656b |
13 | 17133504b48 |
14 | a4593638b1 |
15 | 5824415e3b |
hex | 319e5d49a3 |
213110311331 has 2 divisors, whose sum is σ = 213110311332. Its totient is φ = 213110311330.
The previous prime is 213110311327. The next prime is 213110311333. The reversal of 213110311331 is 133113011312.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 213110311331 - 22 = 213110311327 is a prime.
It is a super-2 number, since 2×2131103113312 (a number of 23 digits) contains 22 as substring.
Together with 213110311333, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (213110311333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106555155665 + 106555155666.
It is an arithmetic number, because the mean of its divisors is an integer number (106555155666).
Almost surely, 2213110311331 is an apocalyptic number.
213110311331 is a deficient number, since it is larger than the sum of its proper divisors (1).
213110311331 is an equidigital number, since it uses as much as digits as its factorization.
213110311331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 20.
Adding to 213110311331 its reverse (133113011312), we get a palindrome (346223322643).
The spelling of 213110311331 in words is "two hundred thirteen billion, one hundred ten million, three hundred eleven thousand, three hundred thirty-one".
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