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2131110331222 = 21065555165611
BaseRepresentation
bin11111000000110000000…
…100110000001101010110
321112201202202001202200111
4133000300010300031112
5234404003221044342
64311004002233234
7306652620634465
oct37006004601526
97481682052614
102131110331222
11751887251224
122a503465581a
13125c69496112
14752095c69dc
153a67d568217
hex1f030130356

2131110331222 has 4 divisors (see below), whose sum is σ = 3196665496836. Its totient is φ = 1065555165610.

The previous prime is 2131110331127. The next prime is 2131110331241. The reversal of 2131110331222 is 2221330111312.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×21311103312222 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2131110331193 and 2131110331202.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 532777582804 + ... + 532777582807.

It is an arithmetic number, because the mean of its divisors is an integer number (799166374209).

Almost surely, 22131110331222 is an apocalyptic number.

2131110331222 is a deficient number, since it is larger than the sum of its proper divisors (1065555165614).

2131110331222 is a wasteful number, since it uses less digits than its factorization.

2131110331222 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1065555165613.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 2131110331222 its reverse (2221330111312), we get a palindrome (4352440442534).

The spelling of 2131110331222 in words is "two trillion, one hundred thirty-one billion, one hundred ten million, three hundred thirty-one thousand, two hundred twenty-two".

Divisors: 1 2 1065555165611 2131110331222