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2131113313100 = 225221311133131
BaseRepresentation
bin11111000000110000010…
…000001000001101001100
321112201202221200021001102
4133000300100020031030
5234404010002004400
64311004150202232
7306652655164142
oct37006020101514
97481687607042
102131113313100
117518889a8592
122a5035653378
13125c69c9b445
1475209b61592
153a67d9569d5
hex1f03040834c

2131113313100 has 18 divisors (see below), whose sum is σ = 4624515889644. Its totient is φ = 852445325200.

The previous prime is 2131113313099. The next prime is 2131113313123. The reversal of 2131113313100 is 13133111312.

It is a super-2 number, since 2×21311133131002 (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 10655566466 + ... + 10655566665.

Almost surely, 22131113313100 is an apocalyptic number.

2131113313100 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

2131113313100 is an abundant number, since it is smaller than the sum of its proper divisors (2493402576544).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2131113313100 is a wasteful number, since it uses less digits than its factorization.

2131113313100 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21311133145 (or 21311133138 counting only the distinct ones).

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 2131113313100 its reverse (13133111312), we get a palindrome (2144246424412).

The spelling of 2131113313100 in words is "two trillion, one hundred thirty-one billion, one hundred thirteen million, three hundred thirteen thousand, one hundred".

Divisors: 1 2 4 5 10 20 25 50 100 21311133131 42622266262 85244532524 106555665655 213111331310 426222662620 532778328275 1065556656550 2131113313100