2131114310031 has 8 divisors (see below), whose sum is σ = 3247412281984. Its totient is φ = 1217779605720.

The previous prime is 2131114309963. The next prime is 2131114310041. The reversal of 2131114310031 is 1300134111312.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 2131114310031 - 2¹⁰ = 2131114309007 is a prime.

It is a super-2 number, since 2×2131114310031² (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (21), and also a Moran number because the ratio is a prime number: 101481633811 = 2131114310031 / (2 + 1 + 3 + 1 + 1 + 1 + 4 + 3 + 1 + 0 + 0 + 3 + 1).

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2131114310041) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 50740816885 + ... + 50740816926.

It is an arithmetic number, because the mean of its divisors is an integer number (405926535248).

Almost surely, 2^{2131114310031} is an apocalyptic number.

2131114310031 is a gapful number since it is divisible by the number (21) formed by its first and last digit.

2131114310031 is a deficient number, since it is larger than the sum of its proper divisors (1116297971953).

2131114310031 is a wasteful number, since it uses less digits than its factorization.

2131114310031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 101481633821.

The product of its (nonzero) digits is 216, while the sum is 21.

Adding to 2131114310031 its reverse (1300134111312), we get a palindrome (3431248421343).

The spelling of 2131114310031 in words is "two trillion, one hundred thirty-one billion, one hundred fourteen million, three hundred ten thousand, thirty-one".