Base | Representation |
---|---|
bin | 1001101100001111001110… |
… | …01011001000010100100011 |
3 | 2210110022221221200102210121 |
4 | 10312013213023020110203 |
5 | 10243130330032210034 |
6 | 113154122452541111 |
7 | 4326453452302633 |
oct | 466074713102443 |
9 | 83408857612717 |
10 | 21311211210019 |
11 | 6877041167255 |
12 | 2482309621797 |
13 | bb783bcb6353 |
14 | 53967a7766c3 |
15 | 26e54816b1b4 |
hex | 1361e72c8523 |
21311211210019 has 2 divisors, whose sum is σ = 21311211210020. Its totient is φ = 21311211210018.
The previous prime is 21311211210011. The next prime is 21311211210031. The reversal of 21311211210019 is 91001211211312.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21311211210019 - 23 = 21311211210011 is a prime.
It is a super-2 number, since 2×213112112100192 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 21311211209975 and 21311211210002.
It is not a weakly prime, because it can be changed into another prime (21311211210011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10655605605009 + 10655605605010.
It is an arithmetic number, because the mean of its divisors is an integer number (10655605605010).
Almost surely, 221311211210019 is an apocalyptic number.
21311211210019 is a deficient number, since it is larger than the sum of its proper divisors (1).
21311211210019 is an equidigital number, since it uses as much as digits as its factorization.
21311211210019 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 25.
The spelling of 21311211210019 in words is "twenty-one trillion, three hundred eleven billion, two hundred eleven million, two hundred ten thousand, nineteen".
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