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213113034392719 = 983921660029921
BaseRepresentation
bin110000011101001100111110…
…101101100100010010001111
31000221120101222210021200111111
4300131030332231210102033
5210413120443301031334
62033130435413232451
762613623442504526
oct6035147655442217
91027511883250444
10213113034392719
11619a480408432a
121ba9a898032727
1391bb61bcaac36
143a8aa23c294bd
15199885be08064
hexc1d33eb6448f

213113034392719 has 4 divisors (see below), whose sum is σ = 213134694432480. Its totient is φ = 213091374352960.

The previous prime is 213113034392663. The next prime is 213113034392729. The reversal of 213113034392719 is 917293430311312.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 213113034392719 - 211 = 213113034390671 is a prime.

It is a super-2 number, since 2×2131130343927192 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (213113034392729) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10830005122 + ... + 10830024799.

It is an arithmetic number, because the mean of its divisors is an integer number (53283673608120).

Almost surely, 2213113034392719 is an apocalyptic number.

213113034392719 is a deficient number, since it is larger than the sum of its proper divisors (21660039761).

213113034392719 is an equidigital number, since it uses as much as digits as its factorization.

213113034392719 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21660039760.

The product of its (nonzero) digits is 734832, while the sum is 49.

The spelling of 213113034392719 in words is "two hundred thirteen trillion, one hundred thirteen billion, thirty-four million, three hundred ninety-two thousand, seven hundred nineteen".

Divisors: 1 9839 21660029921 213113034392719