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213113301131 is a prime number
BaseRepresentation
bin1100011001111010001…
…0101110100010001011
3202101002020021101220002
43012132202232202023
511442424001114011
6241523005353215
721253101112433
oct3063642564213
9671066241802
10213113301131
11824209a2455
123537726880b
1317134010963
14a4599012c3
155824806c3b
hex319e8ae88b

213113301131 has 2 divisors, whose sum is σ = 213113301132. Its totient is φ = 213113301130.

The previous prime is 213113301059. The next prime is 213113301133. The reversal of 213113301131 is 131103311312.

213113301131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 213113301131 - 218 = 213113038987 is a prime.

It is a super-2 number, since 2×2131133011312 (a number of 23 digits) contains 22 as substring.

Together with 213113301133, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (213113301133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106556650565 + 106556650566.

It is an arithmetic number, because the mean of its divisors is an integer number (106556650566).

Almost surely, 2213113301131 is an apocalyptic number.

213113301131 is a deficient number, since it is larger than the sum of its proper divisors (1).

213113301131 is an equidigital number, since it uses as much as digits as its factorization.

213113301131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 213113301131 its reverse (131103311312), we get a palindrome (344216612443).

The spelling of 213113301131 in words is "two hundred thirteen billion, one hundred thirteen million, three hundred one thousand, one hundred thirty-one".