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213113444014061 is a prime number
BaseRepresentation
bin110000011101001101010111…
…001000001001011111101101
31000221120110001100001121100022
4300131031113020021133231
5210413122313131422221
62033130544205011525
762613636545311043
oct6035152710113755
91027513040047308
10213113444014061
11619a49a4320968
121ba9a991253ba5
1391bb685b0a926
143a8aa623b6393
151998882d6c4ab
hexc1d3572097ed

213113444014061 has 2 divisors, whose sum is σ = 213113444014062. Its totient is φ = 213113444014060.

The previous prime is 213113444013979. The next prime is 213113444014073. The reversal of 213113444014061 is 160410444311312.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 208949742548836 + 4163701465225 = 14455094^2 + 2040515^2 .

It is a cyclic number.

It is not a de Polignac number, because 213113444014061 - 242 = 208715397502957 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (213113444019061) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106556722007030 + 106556722007031.

It is an arithmetic number, because the mean of its divisors is an integer number (106556722007031).

Almost surely, 2213113444014061 is an apocalyptic number.

It is an amenable number.

213113444014061 is a deficient number, since it is larger than the sum of its proper divisors (1).

213113444014061 is an equidigital number, since it uses as much as digits as its factorization.

213113444014061 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27648, while the sum is 35.

Adding to 213113444014061 its reverse (160410444311312), we get a palindrome (373523888325373).

The spelling of 213113444014061 in words is "two hundred thirteen trillion, one hundred thirteen billion, four hundred forty-four million, fourteen thousand, sixty-one".