Base | Representation |
---|---|
bin | 110000011101001101100111… |
… | …000011010000010001001011 |
3 | 1000221120110201221202100122112 |
4 | 300131031213003100101023 |
5 | 210413123340024312124 |
6 | 2033131030511012535 |
7 | 62613646301132201 |
oct | 6035154703202113 |
9 | 1027513657670575 |
10 | 213113711166539 |
11 | 619a50210aa537 |
12 | 1ba9aa4680a14b |
13 | 91bb6c9277611 |
14 | 3a8aa89a79071 |
15 | 199889b53d90e |
hex | c1d3670d044b |
213113711166539 has 2 divisors, whose sum is σ = 213113711166540. Its totient is φ = 213113711166538.
The previous prime is 213113711166487. The next prime is 213113711166541. The reversal of 213113711166539 is 935661117311312.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 213113711166539 - 228 = 213113442731083 is a prime.
Together with 213113711166541, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (213113711165539) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106556855583269 + 106556855583270.
It is an arithmetic number, because the mean of its divisors is an integer number (106556855583270).
Almost surely, 2213113711166539 is an apocalyptic number.
213113711166539 is a deficient number, since it is larger than the sum of its proper divisors (1).
213113711166539 is an equidigital number, since it uses as much as digits as its factorization.
213113711166539 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 612360, while the sum is 50.
The spelling of 213113711166539 in words is "two hundred thirteen trillion, one hundred thirteen billion, seven hundred eleven million, one hundred sixty-six thousand, five hundred thirty-nine".
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