Base | Representation |
---|---|
bin | 110000011101001110010000… |
… | …010000010000110000111111 |
3 | 1000221120112112010111210201121 |
4 | 300131032100100100300333 |
5 | 210413131244011123203 |
6 | 2033131223243251411 |
7 | 62614002363646345 |
oct | 6035162020206077 |
9 | 1027515463453647 |
10 | 213114402442303 |
11 | 619a534633021a |
12 | 1ba9abba219b67 |
13 | 91bb7a9550a2b |
14 | 3a8ab137c1995 |
15 | 19988dc08b0bd |
hex | c1d390410c3f |
213114402442303 has 2 divisors, whose sum is σ = 213114402442304. Its totient is φ = 213114402442302.
The previous prime is 213114402442283. The next prime is 213114402442321. The reversal of 213114402442303 is 303244204411312.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 213114402442303 - 221 = 213114400345151 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (213114402472303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106557201221151 + 106557201221152.
It is an arithmetic number, because the mean of its divisors is an integer number (106557201221152).
Almost surely, 2213114402442303 is an apocalyptic number.
213114402442303 is a deficient number, since it is larger than the sum of its proper divisors (1).
213114402442303 is an equidigital number, since it uses as much as digits as its factorization.
213114402442303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 55296, while the sum is 34.
Adding to 213114402442303 its reverse (303244204411312), we get a palindrome (516358606853615).
The spelling of 213114402442303 in words is "two hundred thirteen trillion, one hundred fourteen billion, four hundred two million, four hundred forty-two thousand, three hundred three".
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