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2131201000001 = 14991421748499
BaseRepresentation
bin11111000000110101011…
…110101000001001000001
321112202000001200012212102
4133000311132220021001
5234404144424000001
64311021001440145
7306655101414113
oct37006536501101
97482001605772
102131201000001
11751923449aa7
122a505aaa0055
13125c821c0598
14752176693b3
153a6864c7e6b
hex1f0357a8241

2131201000001 has 4 divisors (see below), whose sum is σ = 2132622750000. Its totient is φ = 2129779250004.

The previous prime is 2131200999997. The next prime is 2131201000013. The reversal of 2131201000001 is 1000001021312.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2131201000001 - 22 = 2131200999997 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2131201002001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 710872751 + ... + 710875748.

It is an arithmetic number, because the mean of its divisors is an integer number (533155687500).

Almost surely, 22131201000001 is an apocalyptic number.

It is an amenable number.

2131201000001 is a deficient number, since it is larger than the sum of its proper divisors (1421749999).

2131201000001 is a wasteful number, since it uses less digits than its factorization.

2131201000001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1421749998.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 2131201000001 its reverse (1000001021312), we get a palindrome (3131202021313).

It can be divided in two parts, 213120 and 1000001, that added together give a palindrome (1213121).

The spelling of 2131201000001 in words is "two trillion, one hundred thirty-one billion, two hundred one million, one", and thus it is an aban number.

Divisors: 1 1499 1421748499 2131201000001