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213120113131 = 1712536477243
BaseRepresentation
bin1100011001111011110…
…0101101100111101011
3202101002201002111012101
43012132330231213223
511442432222110011
6241523411354231
721253213033462
oct3063674554753
9671081074171
10213120113131
1182424825402
12353795b2977
1317135557423
14a45a7959d9
1558252002c1
hex319ef2d9eb

213120113131 has 4 divisors (see below), whose sum is σ = 225656590392. Its totient is φ = 200583635872.

The previous prime is 213120113123. The next prime is 213120113147. The reversal of 213120113131 is 131311021312.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 213120113131 - 23 = 213120113123 is a prime.

It is a super-2 number, since 2×2131201131312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 213120113099 and 213120113108.

It is not an unprimeable number, because it can be changed into a prime (213120113111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6268238605 + ... + 6268238638.

It is an arithmetic number, because the mean of its divisors is an integer number (56414147598).

Almost surely, 2213120113131 is an apocalyptic number.

213120113131 is a deficient number, since it is larger than the sum of its proper divisors (12536477261).

213120113131 is a wasteful number, since it uses less digits than its factorization.

213120113131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12536477260.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 213120113131 its reverse (131311021312), we get a palindrome (344431134443).

The spelling of 213120113131 in words is "two hundred thirteen billion, one hundred twenty million, one hundred thirteen thousand, one hundred thirty-one".

Divisors: 1 17 12536477243 213120113131