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213120200203 = 2350111849151
BaseRepresentation
bin1100011001111011110…
…1000010111000001011
3202101002201020220122021
43012132331002320023
511442432232401303
6241523413305311
721253213545361
oct3063675027013
9671081226567
10213120200203
1182424884869
1235379635237
1317135587c51
14a45a7b9631
15582521aebd
hex319ef42e0b

213120200203 has 8 divisors (see below), whose sum is σ = 222430795776. Its totient is φ = 203813313000.

The previous prime is 213120200159. The next prime is 213120200219. The reversal of 213120200203 is 302002021312.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-213120200203 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (213120200603) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 809323 + ... + 1039828.

It is an arithmetic number, because the mean of its divisors is an integer number (27803849472).

Almost surely, 2213120200203 is an apocalyptic number.

213120200203 is a gapful number since it is divisible by the number (23) formed by its first and last digit.

213120200203 is a deficient number, since it is larger than the sum of its proper divisors (9310595573).

213120200203 is a wasteful number, since it uses less digits than its factorization.

213120200203 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1854185.

The product of its (nonzero) digits is 144, while the sum is 16.

Adding to 213120200203 its reverse (302002021312), we get a palindrome (515122221515).

The spelling of 213120200203 in words is "two hundred thirteen billion, one hundred twenty million, two hundred thousand, two hundred three".

Divisors: 1 23 5011 115253 1849151 42530473 9266095661 213120200203