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21312032201183 is a prime number
BaseRepresentation
bin1001101100010000110000…
…00110111101100111011111
32210110102002011112002221202
410312020120012331213133
510243134020220414213
6113154340141350115
74326513011514113
oct466103006754737
983412064462852
1021312032201183
116877422635049
1224824b856833b
13bb7940108839
14539717807743
1526e59528cb58
hex1362181bd9df

21312032201183 has 2 divisors, whose sum is σ = 21312032201184. Its totient is φ = 21312032201182.

The previous prime is 21312032201107. The next prime is 21312032201189. The reversal of 21312032201183 is 38110223021312.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-21312032201183 is a prime.

It is a super-2 number, since 2×213120322011832 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21312032201189) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10656016100591 + 10656016100592.

It is an arithmetic number, because the mean of its divisors is an integer number (10656016100592).

Almost surely, 221312032201183 is an apocalyptic number.

21312032201183 is a deficient number, since it is larger than the sum of its proper divisors (1).

21312032201183 is an equidigital number, since it uses as much as digits as its factorization.

21312032201183 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3456, while the sum is 29.

Adding to 21312032201183 its reverse (38110223021312), we get a palindrome (59422255222495).

The spelling of 21312032201183 in words is "twenty-one trillion, three hundred twelve billion, thirty-two million, two hundred one thousand, one hundred eighty-three".