Base | Representation |
---|---|
bin | 110000011101010101010110… |
… | …010111100101111100000111 |
3 | 1000221121021012002120211002011 |
4 | 300131111112113211330013 |
5 | 210413242344413020403 |
6 | 2033134523244155051 |
7 | 62614362235333462 |
oct | 6035252627457407 |
9 | 1027537162524064 |
10 | 213122021220103 |
11 | 619a85a59987a6 |
12 | 1baa0585838a87 |
13 | 91bc421ac8588 |
14 | 3a8b2375b22d9 |
15 | 1998bd5d81a6d |
hex | c1d5565e5f07 |
213122021220103 has 2 divisors, whose sum is σ = 213122021220104. Its totient is φ = 213122021220102.
The previous prime is 213122021220049. The next prime is 213122021220107. The reversal of 213122021220103 is 301022120221312.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 213122021220103 - 241 = 210922997964551 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (213122021220107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106561010610051 + 106561010610052.
It is an arithmetic number, because the mean of its divisors is an integer number (106561010610052).
Almost surely, 2213122021220103 is an apocalyptic number.
213122021220103 is a deficient number, since it is larger than the sum of its proper divisors (1).
213122021220103 is an equidigital number, since it uses as much as digits as its factorization.
213122021220103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 22.
Adding to 213122021220103 its reverse (301022120221312), we get a palindrome (514144141441415).
The spelling of 213122021220103 in words is "two hundred thirteen trillion, one hundred twenty-two billion, twenty-one million, two hundred twenty thousand, one hundred three".
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