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21312234505283 is a prime number
BaseRepresentation
bin1001101100010001001000…
…01010101100010001000011
32210110102121021012020000012
410312020210022230101003
510243134424013132113
6113154412205415135
74326521016206021
oct466104412542103
983412537166005
1021312234505283
116877516851117
12248255426a4ab
13bb7972cbb7c7
14539736629711
1526e5a7deeaa8
hex1362242ac443

21312234505283 has 2 divisors, whose sum is σ = 21312234505284. Its totient is φ = 21312234505282.

The previous prime is 21312234505189. The next prime is 21312234505307. The reversal of 21312234505283 is 38250543221312.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 21312234505283 - 210 = 21312234504259 is a prime.

It is a super-2 number, since 2×213122345052832 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 21312234505283.

It is not a weakly prime, because it can be changed into another prime (21312234505883) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10656117252641 + 10656117252642.

It is an arithmetic number, because the mean of its divisors is an integer number (10656117252642).

Almost surely, 221312234505283 is an apocalyptic number.

21312234505283 is a deficient number, since it is larger than the sum of its proper divisors (1).

21312234505283 is an equidigital number, since it uses as much as digits as its factorization.

21312234505283 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 345600, while the sum is 41.

Adding to 21312234505283 its reverse (38250543221312), we get a palindrome (59562777726595).

The spelling of 21312234505283 in words is "twenty-one trillion, three hundred twelve billion, two hundred thirty-four million, five hundred five thousand, two hundred eighty-three".