Base | Representation |
---|---|
bin | 110000011101011101110011… |
… | …100101111000100000100010 |
3 | 1000221122010121220121210011001 |
4 | 300131131303211320200202 |
5 | 210413414443432040114 |
6 | 2033143024252542214 |
7 | 62615133244045051 |
oct | 6035356345704042 |
9 | 1027563556553131 |
10 | 213131101440034 |
11 | 61a014354a0398 |
12 | 1baa229a78196a |
13 | 91c023b08508b |
14 | 3a8b85950a398 |
15 | 1999068107374 |
hex | c1d773978822 |
213131101440034 has 4 divisors (see below), whose sum is σ = 319696652160054. Its totient is φ = 106565550720016.
The previous prime is 213131101440031. The next prime is 213131101440097. The reversal of 213131101440034 is 430044101131312.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 139639007441025 + 73492093999009 = 11816895^2 + 8572753^2 .
It is a junction number, because it is equal to n+sod(n) for n = 213131101439984 and 213131101440011.
It is not an unprimeable number, because it can be changed into a prime (213131101440031) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 53282775360007 + ... + 53282775360010.
Almost surely, 2213131101440034 is an apocalyptic number.
213131101440034 is a deficient number, since it is larger than the sum of its proper divisors (106565550720020).
213131101440034 is a wasteful number, since it uses less digits than its factorization.
213131101440034 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 106565550720019.
The product of its (nonzero) digits is 3456, while the sum is 28.
Adding to 213131101440034 its reverse (430044101131312), we get a palindrome (643175202571346).
The spelling of 213131101440034 in words is "two hundred thirteen trillion, one hundred thirty-one billion, one hundred one million, four hundred forty thousand, thirty-four".
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