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213131222012207 is a prime number
BaseRepresentation
bin110000011101011101111010…
…110001110101000100101111
31000221122010221022111111002002
4300131131322301311010233
5210413420220313342312
62033143044241122515
762615136236641322
oct6035357261650457
91027563838444062
10213131222012207
1161a01497563014
121baa231302943b
1391c025a04c565
143a8b86b5347b9
1519990739c24c2
hexc1d77ac7512f

213131222012207 has 2 divisors, whose sum is σ = 213131222012208. Its totient is φ = 213131222012206.

The previous prime is 213131222012179. The next prime is 213131222012257. The reversal of 213131222012207 is 702210222131312.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 213131222012207 - 218 = 213131221750063 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 213131222012207.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (213131222012257) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106565611006103 + 106565611006104.

It is an arithmetic number, because the mean of its divisors is an integer number (106565611006104).

Almost surely, 2213131222012207 is an apocalyptic number.

213131222012207 is a deficient number, since it is larger than the sum of its proper divisors (1).

213131222012207 is an equidigital number, since it uses as much as digits as its factorization.

213131222012207 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4032, while the sum is 29.

Adding to 213131222012207 its reverse (702210222131312), we get a palindrome (915341444143519).

The spelling of 213131222012207 in words is "two hundred thirteen trillion, one hundred thirty-one billion, two hundred twenty-two million, twelve thousand, two hundred seven".