Search a number
-
+
21313200311189 is a prime number
BaseRepresentation
bin1001101100010010111011…
…01110111100101110010101
32210110112002120112020122022
410312021131232330232111
510243143413234424224
6113155052110142525
74326553654342463
oct466113556745625
983415076466568
1021313200311189
116877971a3a416
1224827837b1a45
13bb7a981159a7
145397c89d5833
1526e612ac965e
hex13625dbbcb95

21313200311189 has 2 divisors, whose sum is σ = 21313200311190. Its totient is φ = 21313200311188.

The previous prime is 21313200311149. The next prime is 21313200311203. The reversal of 21313200311189 is 98111300231312.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 18155354028100 + 3157846283089 = 4260910^2 + 1777033^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-21313200311189 is a prime.

It is a super-3 number, since 3×213132003111893 (a number of 41 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21313200311119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10656600155594 + 10656600155595.

It is an arithmetic number, because the mean of its divisors is an integer number (10656600155595).

Almost surely, 221313200311189 is an apocalyptic number.

It is an amenable number.

21313200311189 is a deficient number, since it is larger than the sum of its proper divisors (1).

21313200311189 is an equidigital number, since it uses as much as digits as its factorization.

21313200311189 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7776, while the sum is 35.

The spelling of 21313200311189 in words is "twenty-one trillion, three hundred thirteen billion, two hundred million, three hundred eleven thousand, one hundred eighty-nine".