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213132113 = 682731219
BaseRepresentation
bin11001011010000…
…10001101010001
3112212001020021222
430231002031101
5414030211423
633052054425
75165410265
oct1455021521
9485036258
10213132113
11aa342347
125b464415
133520469c
14204400a5
1513aa03c8
hexcb42351

213132113 has 4 divisors (see below), whose sum is σ = 213170160. Its totient is φ = 213094068.

The previous prime is 213132091. The next prime is 213132137. The reversal of 213132113 is 311231312.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 213132113 - 210 = 213131089 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 213132091 and 213132100.

It is not an unprimeable number, because it can be changed into a prime (213132193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8783 + ... + 22436.

It is an arithmetic number, because the mean of its divisors is an integer number (53292540).

Almost surely, 2213132113 is an apocalyptic number.

It is an amenable number.

213132113 is a deficient number, since it is larger than the sum of its proper divisors (38047).

213132113 is an equidigital number, since it uses as much as digits as its factorization.

213132113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 38046.

The product of its digits is 108, while the sum is 17.

The square root of 213132113 is about 14599.0449345154. The cubic root of 213132113 is about 597.3327092447.

Adding to 213132113 its reverse (311231312), we get a palindrome (524363425).

The spelling of 213132113 in words is "two hundred thirteen million, one hundred thirty-two thousand, one hundred thirteen".

Divisors: 1 6827 31219 213132113