Base | Representation |
---|---|
bin | 1001101100010010111101… |
… | …11011001111100001101011 |
3 | 2210110112010222011100102111 |
4 | 10312021132323033201223 |
5 | 10243143433344424042 |
6 | 113155054102543151 |
7 | 4326554316341422 |
oct | 466113673174153 |
9 | 83415128140374 |
10 | 21313220311147 |
11 | 687798225a706 |
12 | 248278a437ab7 |
13 | bb7a9c2c909b |
14 | 5397cb5202b9 |
15 | 26e61472a517 |
hex | 13625eecf86b |
21313220311147 has 2 divisors, whose sum is σ = 21313220311148. Its totient is φ = 21313220311146.
The previous prime is 21313220311109. The next prime is 21313220311199. The reversal of 21313220311147 is 74111302231312.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21313220311147 - 215 = 21313220278379 is a prime.
It is not a weakly prime, because it can be changed into another prime (21313220311247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10656610155573 + 10656610155574.
It is an arithmetic number, because the mean of its divisors is an integer number (10656610155574).
Almost surely, 221313220311147 is an apocalyptic number.
21313220311147 is a deficient number, since it is larger than the sum of its proper divisors (1).
21313220311147 is an equidigital number, since it uses as much as digits as its factorization.
21313220311147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6048, while the sum is 31.
Adding to 21313220311147 its reverse (74111302231312), we get a palindrome (95424522542459).
The spelling of 21313220311147 in words is "twenty-one trillion, three hundred thirteen billion, two hundred twenty million, three hundred eleven thousand, one hundred forty-seven".
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