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213140320403 = 348991610733
BaseRepresentation
bin1100011010000000100…
…1110011000010010011
3202101011010010010100212
43012200021303002103
511443002410223103
6241525412434335
721253546555013
oct3064011630223
9671133103325
10213140320403
118243517742a
12353843189ab
13171397b0caa
14a45d335c43
155826d927d8
hex31a0273093

213140320403 has 4 divisors (see below), whose sum is σ = 213141280128. Its totient is φ = 213139360680.

The previous prime is 213140320399. The next prime is 213140320423. The reversal of 213140320403 is 304023041312.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 213140320403 - 22 = 213140320399 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (213140320423) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43625 + ... + 654357.

It is an arithmetic number, because the mean of its divisors is an integer number (53285320032).

Almost surely, 2213140320403 is an apocalyptic number.

213140320403 is a deficient number, since it is larger than the sum of its proper divisors (959725).

213140320403 is an equidigital number, since it uses as much as digits as its factorization.

213140320403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 959724.

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 213140320403 its reverse (304023041312), we get a palindrome (517163361715).

The spelling of 213140320403 in words is "two hundred thirteen billion, one hundred forty million, three hundred twenty thousand, four hundred three".

Divisors: 1 348991 610733 213140320403