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2131404444431 is a prime number
BaseRepresentation
bin11111000001000001100…
…110101101001100001111
321112202112020111021011022
4133001001212231030033
5234410104014210211
64311053110144355
7306663121565423
oct37010146551417
97482466437138
102131404444431
11751a18274899
122a50b70520bb
13125cb53b25c2
14752366a6b83
153a6992b2bdb
hex1f0419ad30f

2131404444431 has 2 divisors, whose sum is σ = 2131404444432. Its totient is φ = 2131404444430.

The previous prime is 2131404444427. The next prime is 2131404444479. The reversal of 2131404444431 is 1344444041312.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2131404444431 - 22 = 2131404444427 is a prime.

It is a super-2 number, since 2×21314044444312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2131404444391 and 2131404444400.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2131404441431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1065702222215 + 1065702222216.

It is an arithmetic number, because the mean of its divisors is an integer number (1065702222216).

Almost surely, 22131404444431 is an apocalyptic number.

2131404444431 is a deficient number, since it is larger than the sum of its proper divisors (1).

2131404444431 is an equidigital number, since it uses as much as digits as its factorization.

2131404444431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 73728, while the sum is 35.

Adding to 2131404444431 its reverse (1344444041312), we get a palindrome (3475848485743).

The spelling of 2131404444431 in words is "two trillion, one hundred thirty-one billion, four hundred four million, four hundred forty-four thousand, four hundred thirty-one".