Base | Representation |
---|---|
bin | 110000011101100111001111… |
… | …011100100011001110100111 |
3 | 1000221200002202221212111112011 |
4 | 300131213033130203032213 |
5 | 210414101221000311124 |
6 | 2033151421435135051 |
7 | 62615642302051642 |
oct | 6035471734431647 |
9 | 1027602687774464 |
10 | 213141232432039 |
11 | 61a0576414465a |
12 | 1baa42475a4487 |
13 | 91c1193c476c2 |
14 | 3a8c13ac0aa59 |
15 | 199945c73c994 |
hex | c1d9cf7233a7 |
213141232432039 has 2 divisors, whose sum is σ = 213141232432040. Its totient is φ = 213141232432038.
The previous prime is 213141232432031. The next prime is 213141232432057. The reversal of 213141232432039 is 930234232141312.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 213141232432039 - 23 = 213141232432031 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 213141232431992 and 213141232432010.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (213141232432031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106570616216019 + 106570616216020.
It is an arithmetic number, because the mean of its divisors is an integer number (106570616216020).
Almost surely, 2213141232432039 is an apocalyptic number.
213141232432039 is a deficient number, since it is larger than the sum of its proper divisors (1).
213141232432039 is an equidigital number, since it uses as much as digits as its factorization.
213141232432039 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 186624, while the sum is 40.
The spelling of 213141232432039 in words is "two hundred thirteen trillion, one hundred forty-one billion, two hundred thirty-two million, four hundred thirty-two thousand, thirty-nine".
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