Base | Representation |
---|---|
bin | 10011110110011011… |
… | …010101110010000111 |
3 | 2001000102111010211221 |
4 | 103312123111302013 |
5 | 322122420401211 |
6 | 13442553541211 |
7 | 1353120656263 |
oct | 236633256207 |
9 | 61012433757 |
10 | 21314231431 |
11 | 90483675a9 |
12 | 416a114807 |
13 | 2018a5647c |
14 | 1062a6d0a3 |
15 | 84b31cc71 |
hex | 4f66d5c87 |
21314231431 has 2 divisors, whose sum is σ = 21314231432. Its totient is φ = 21314231430.
The previous prime is 21314231333. The next prime is 21314231441. The reversal of 21314231431 is 13413241312.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21314231431 - 27 = 21314231303 is a prime.
It is a super-2 number, since 2×213142314312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 21314231396 and 21314231405.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21314231441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10657115715 + 10657115716.
It is an arithmetic number, because the mean of its divisors is an integer number (10657115716).
Almost surely, 221314231431 is an apocalyptic number.
21314231431 is a deficient number, since it is larger than the sum of its proper divisors (1).
21314231431 is an equidigital number, since it uses as much as digits as its factorization.
21314231431 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1728, while the sum is 25.
Adding to 21314231431 its reverse (13413241312), we get a palindrome (34727472743).
The spelling of 21314231431 in words is "twenty-one billion, three hundred fourteen million, two hundred thirty-one thousand, four hundred thirty-one".
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