Base | Representation |
---|---|
bin | 11111000001000011011… |
… | …000110000101010011011 |
3 | 21112202121022202021101012 |
4 | 133001003120300222123 |
5 | 234410134142434232 |
6 | 4311100055044135 |
7 | 306663633662441 |
oct | 37010330605233 |
9 | 7482538667335 |
10 | 2131434343067 |
11 | 751a33136107 |
12 | 2a510507064b |
13 | 125cbb6503c3 |
14 | 7523a64ab91 |
15 | 3a69bc1b9b2 |
hex | 1f043630a9b |
2131434343067 has 2 divisors, whose sum is σ = 2131434343068. Its totient is φ = 2131434343066.
The previous prime is 2131434343063. The next prime is 2131434343249. The reversal of 2131434343067 is 7603434341312.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2131434343067 - 22 = 2131434343063 is a prime.
It is not a weakly prime, because it can be changed into another prime (2131434343063) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1065717171533 + 1065717171534.
It is an arithmetic number, because the mean of its divisors is an integer number (1065717171534).
Almost surely, 22131434343067 is an apocalyptic number.
2131434343067 is a deficient number, since it is larger than the sum of its proper divisors (1).
2131434343067 is an equidigital number, since it uses as much as digits as its factorization.
2131434343067 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 435456, while the sum is 41.
Adding to 2131434343067 its reverse (7603434341312), we get a palindrome (9734868684379).
The spelling of 2131434343067 in words is "two trillion, one hundred thirty-one billion, four hundred thirty-four million, three hundred forty-three thousand, sixty-seven".
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