Base | Representation |
---|---|
bin | 11111000001000011011… |
… | …000110000101101010001 |
3 | 21112202121022202021121221 |
4 | 133001003120300231101 |
5 | 234410134142440444 |
6 | 4311100055045041 |
7 | 306663633663121 |
oct | 37010330605521 |
9 | 7482538667557 |
10 | 2131434343249 |
11 | 751a33136262 |
12 | 2a5105070781 |
13 | 125cbb650503 |
14 | 7523a64ac81 |
15 | 3a69bc1ba84 |
hex | 1f043630b51 |
2131434343249 has 2 divisors, whose sum is σ = 2131434343250. Its totient is φ = 2131434343248.
The previous prime is 2131434343067. The next prime is 2131434343253. The reversal of 2131434343249 is 9423434341312.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2120867942400 + 10566400849 = 1456320^2 + 102793^2 .
It is a cyclic number.
It is not a de Polignac number, because 2131434343249 - 213 = 2131434335057 is a prime.
It is a super-3 number, since 3×21314343432493 (a number of 38 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (2131434343849) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1065717171624 + 1065717171625.
It is an arithmetic number, because the mean of its divisors is an integer number (1065717171625).
Almost surely, 22131434343249 is an apocalyptic number.
It is an amenable number.
2131434343249 is a deficient number, since it is larger than the sum of its proper divisors (1).
2131434343249 is an equidigital number, since it uses as much as digits as its factorization.
2131434343249 is an evil number, because the sum of its binary digits is even.
The product of its digits is 746496, while the sum is 43.
The spelling of 2131434343249 in words is "two trillion, one hundred thirty-one billion, four hundred thirty-four million, three hundred forty-three thousand, two hundred forty-nine".
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