Base | Representation |
---|---|
bin | 10011110110011100… |
… | …000000011100000111 |
3 | 2001000102211000112001 |
4 | 103312130000130013 |
5 | 322122441444101 |
6 | 13443001410131 |
7 | 1353122314543 |
oct | 236634003407 |
9 | 61012730461 |
10 | 21314406151 |
11 | 90484768a5 |
12 | 416a199947 |
13 | 2018ab7b5c |
14 | 1062ab6a23 |
15 | 84b354901 |
hex | 4f6700707 |
21314406151 has 2 divisors, whose sum is σ = 21314406152. Its totient is φ = 21314406150.
The previous prime is 21314406143. The next prime is 21314406163. The reversal of 21314406151 is 15160441312.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21314406151 - 23 = 21314406143 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21314406121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10657203075 + 10657203076.
It is an arithmetic number, because the mean of its divisors is an integer number (10657203076).
Almost surely, 221314406151 is an apocalyptic number.
21314406151 is a deficient number, since it is larger than the sum of its proper divisors (1).
21314406151 is an equidigital number, since it uses as much as digits as its factorization.
21314406151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2880, while the sum is 28.
Adding to 21314406151 its reverse (15160441312), we get a palindrome (36474847463).
The spelling of 21314406151 in words is "twenty-one billion, three hundred fourteen million, four hundred six thousand, one hundred fifty-one".
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