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21314504767 = 29734982923
BaseRepresentation
bin10011110110011100…
…011000100000111111
32001000110000000210111
4103312130120200333
5322123003123032
613443003450451
71353123205213
oct236634304077
961013000714
1021314504767
1190485339a6
12416a226a27
132018b209ca
141062b00943
1584b373c47
hex4f671883f

21314504767 has 4 divisors (see below), whose sum is σ = 22049487720. Its totient is φ = 20579521816.

The previous prime is 21314504711. The next prime is 21314504773. The reversal of 21314504767 is 76740541312.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 21314504767 - 211 = 21314502719 is a prime.

It is a super-2 number, since 2×213145047672 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21314534767) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 367491433 + ... + 367491490.

It is an arithmetic number, because the mean of its divisors is an integer number (5512371930).

Almost surely, 221314504767 is an apocalyptic number.

21314504767 is a deficient number, since it is larger than the sum of its proper divisors (734982953).

21314504767 is an equidigital number, since it uses as much as digits as its factorization.

21314504767 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 734982952.

The product of its (nonzero) digits is 141120, while the sum is 40.

The spelling of 21314504767 in words is "twenty-one billion, three hundred fourteen million, five hundred four thousand, seven hundred sixty-seven".

Divisors: 1 29 734982923 21314504767