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21315011125 = 53475961493
BaseRepresentation
bin10011110110011110…
…010100001000110101
32001000110221202101111
4103312132110020311
5322123120324000
613443022355021
71353130414402
oct236636241065
961013852344
1021315011125
11904884a381
12416a42ba71
132018c6a325
141062bd32a9
1584b423cba
hex4f6794235

21315011125 has 32 divisors (see below), whose sum is σ = 27628024320. Its totient is φ = 16406065600.

The previous prime is 21315011117. The next prime is 21315011131. The reversal of 21315011125 is 52111051312.

It is not a de Polignac number, because 21315011125 - 23 = 21315011117 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 21315011096 and 21315011105.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 315879 + ... + 377371.

It is an arithmetic number, because the mean of its divisors is an integer number (863375760).

Almost surely, 221315011125 is an apocalyptic number.

21315011125 is a gapful number since it is divisible by the number (25) formed by its first and last digit.

It is an amenable number.

21315011125 is a deficient number, since it is larger than the sum of its proper divisors (6313013195).

21315011125 is an equidigital number, since it uses as much as digits as its factorization.

21315011125 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 61614 (or 61604 counting only the distinct ones).

The product of its (nonzero) digits is 300, while the sum is 22.

Adding to 21315011125 its reverse (52111051312), we get a palindrome (73426062437).

The spelling of 21315011125 in words is "twenty-one billion, three hundred fifteen million, eleven thousand, one hundred twenty-five".

Divisors: 1 5 25 47 59 125 235 295 1175 1475 2773 5875 7375 13865 61493 69325 307465 346625 1537325 2890171 3628087 7686625 14450855 18140435 72254275 90702175 170520089 361271375 453510875 852600445 4263002225 21315011125