Base | Representation |
---|---|
bin | 1100011010001110110… |
… | …1100000000010001011 |
3 | 202101022021102202000122 |
4 | 3012203231200002023 |
5 | 11443113200331103 |
6 | 241535344053455 |
7 | 21255203124161 |
oct | 3064355400213 |
9 | 671267382018 |
10 | 213200011403 |
11 | 82465937135 |
12 | 353a030428b |
13 | 17148c80402 |
14 | a467233231 |
15 | 582c233b38 |
hex | 31a3b6008b |
213200011403 has 2 divisors, whose sum is σ = 213200011404. Its totient is φ = 213200011402.
The previous prime is 213200011361. The next prime is 213200011411. The reversal of 213200011403 is 304110002312.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 213200011403 - 28 = 213200011147 is a prime.
It is not a weakly prime, because it can be changed into another prime (213200010403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106600005701 + 106600005702.
It is an arithmetic number, because the mean of its divisors is an integer number (106600005702).
Almost surely, 2213200011403 is an apocalyptic number.
213200011403 is a deficient number, since it is larger than the sum of its proper divisors (1).
213200011403 is an equidigital number, since it uses as much as digits as its factorization.
213200011403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 213200011403 its reverse (304110002312), we get a palindrome (517310013715).
Subtracting 213200011403 from its reverse (304110002312), we obtain a palindrome (90909990909).
The spelling of 213200011403 in words is "two hundred thirteen billion, two hundred million, eleven thousand, four hundred three".
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