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2132011201322 = 21066005600661
BaseRepresentation
bin11111000001100101110…
…001010011001100101010
321112211002112012201010202
4133001211301103030222
5234412324331420242
64311233223112202
7310014140126102
oct37014561231452
97484075181122
102132011201322
117521a9818272
122a52462a2662
13126081005852
14752930cc202
153a6d26b7932
hex1f065c5332a

2132011201322 has 4 divisors (see below), whose sum is σ = 3198016801986. Its totient is φ = 1066005600660.

The previous prime is 2132011201297. The next prime is 2132011201343. The reversal of 2132011201322 is 2231021102312.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 1555081326841 + 576929874481 = 1247029^2 + 759559^2 .

It is a super-2 number, since 2×21320112013222 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2132011201294 and 2132011201303.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 533002800329 + ... + 533002800332.

Almost surely, 22132011201322 is an apocalyptic number.

2132011201322 is a deficient number, since it is larger than the sum of its proper divisors (1066005600664).

2132011201322 is a wasteful number, since it uses less digits than its factorization.

2132011201322 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1066005600663.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 2132011201322 its reverse (2231021102312), we get a palindrome (4363032303634).

The spelling of 2132011201322 in words is "two trillion, one hundred thirty-two billion, eleven million, two hundred one thousand, three hundred twenty-two".

Divisors: 1 2 1066005600661 2132011201322